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(d/dx){log(secx+tanx)}=
- a)cos x
- b)sec x
- c)tan x
- d)cot x
Correct answer is option 'B'. Can you explain this answer?
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(d/dx){log(secx+tanx)}=a)cos xb)sec xc)tan xd)cot xCorrect answer is o...
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(d/dx){log(secx+tanx)}=a)cos xb)sec xc)tan xd)cot xCorrect answer is o...
Explanation:
Given function:
Let's first write down the given function:
f(x) = log(sec(x) + tan(x))
Derivative of the given function:
To find the derivative of the given function, we will use the chain rule. The derivative of log(u) is 1/u times the derivative of u.
So, we have:
(f(x))' = (1/(sec(x) + tan(x))) * (sec(x) + tan(x))'
= (sec(x) + tan(x))' / (sec(x) + tan(x))
= (sec(x)tan(x) + sec^2(x)) / (sec(x) + tan(x))
= sec(x)(tan(x) + sec(x)) / (sec(x) + tan(x))
= sec(x)
Correct answer:
From the derivative we found above, we can see that the correct answer is option B. sec x. The derivative of log(sec(x) + tan(x)) with respect to x is sec x.
Given function:
Let's first write down the given function:
f(x) = log(sec(x) + tan(x))
Derivative of the given function:
To find the derivative of the given function, we will use the chain rule. The derivative of log(u) is 1/u times the derivative of u.
So, we have:
(f(x))' = (1/(sec(x) + tan(x))) * (sec(x) + tan(x))'
= (sec(x) + tan(x))' / (sec(x) + tan(x))
= (sec(x)tan(x) + sec^2(x)) / (sec(x) + tan(x))
= sec(x)(tan(x) + sec(x)) / (sec(x) + tan(x))
= sec(x)
Correct answer:
From the derivative we found above, we can see that the correct answer is option B. sec x. The derivative of log(sec(x) + tan(x)) with respect to x is sec x.
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(d/dx){log(secx+tanx)}=a)cos xb)sec xc)tan xd)cot xCorrect answer is option 'B'. Can you explain this answer?
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(d/dx){log(secx+tanx)}=a)cos xb)sec xc)tan xd)cot xCorrect answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about (d/dx){log(secx+tanx)}=a)cos xb)sec xc)tan xd)cot xCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for (d/dx){log(secx+tanx)}=a)cos xb)sec xc)tan xd)cot xCorrect answer is option 'B'. Can you explain this answer?.
(d/dx){log(secx+tanx)}=a)cos xb)sec xc)tan xd)cot xCorrect answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about (d/dx){log(secx+tanx)}=a)cos xb)sec xc)tan xd)cot xCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for (d/dx){log(secx+tanx)}=a)cos xb)sec xc)tan xd)cot xCorrect answer is option 'B'. Can you explain this answer?.
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